Mar 29, 2014 · const char* cstyle = input.c_str(); If you use a C-style string, the last character is always the null terminator '\0' to indicate the end of the string. This is important to know where …

Aug 24, 2016 · 1 There is no string data type in C programming language. Strings in C are represented as array of characters. In C, char is a data type to represent a character. So, all …

May 11, 2011 · If you use the nextLine () method immediately following the nextInt () method, nextInt () reads integer tokens; because of this, the last newline character for that line of …

I am trying to take string input in java using Scanner, but before that I am taking an integer input. Here is my code. import java.util.*; class prc { public static void main (String [] args) ...

Dec 6, 2016 · There is a reason behind taking age (int type) followed by fullName (string type) followed by rollNumber (int type). If we try to get around this problem using some other way …

Jan 18, 2017 · A C-string is a sequence of bytes terminated by null character. Therefore we can always know the end of the string. Even if we point at a memory location which does not …

247 I have an input string and I want to verify that it contains: Only letters or Only letters and numbers or Only letters, numbers or underscore To clarify, I have 3 different cases in the …

Jan 30, 2016 · Read a string as an input using scanf Asked 9 years, 10 months ago Modified 6 years ago Viewed 113k times

Well, std::string is a class, const char * is a pointer. Those are two different things. It's easy to get from string to a pointer (since it typically contains one that it can just return), but for the other …

Scanner breaks its input into tokens using a delimiter pattern, which by default matches whitespace (\s) and it is recognised by Character.isWhitespace. « Until the user enters data, …